Theory of Income · Part III: OLG Extensions (Class Note III) · Lesson 15 of 25

OLG with Capital: Social Security and Capital Accumulation

Covers Class Note III, pp. 15–19 · About 40 min · Prerequisites: Lesson 11, Lesson 14
By the end you can:
  1. explain the timing of capital, rental rates and interest rates, and derive \(r_t = F_K(K_{t+1},1)-\delta\);
  2. show that household budgets, the government budget and goods-market clearing imply \(B_t + s_t = K_{t+1}\) (Walras' law with capital);
  3. sign the effect of pay-as-you-go (PAYG) social security on saving and on the steady-state capital stock, and explain why the sign flips at an unstable steady state;
  4. work through the Cobb–Douglas example: show that generation 1 can gain even when \(r>0\), and that steady-state generations lose exactly when \(r>0\).
Primary source Alvarez, Class Note III, pp. 15–19. The model with capital is due to Diamond, P. (1965), “National Debt in a Neoclassical Growth Model,” American Economic Review 55(5): 1126–1150 (free PDF from the AEA). Sections I–III are the relevant part.
Notation alert

1. From endowments to production

So far the OLG economy had no way to move goods through time except trade between generations. Now we add a storable, productive asset: capital. One generation is born each period, of constant size one (no population growth). There is a constant-returns production function \(F(K,L)\), and capital depreciates at rate \(\delta\) III p.15:

$$K_{t+1} = I_t + (1-\delta)K_t, \qquad g_t + I_t + C_t = F(K_t, L_t), \qquad C_t = c^t_t + c^{t-1}_t .$$

Labour is supplied inelastically by the young, so \(L_t = 1\) throughout.

2. Factor prices and the timing of the interest rate

A competitive firm rents capital at rental rate \(v_t\) and hires labour at wage \(w_t\). With constant returns and price-taking,

$$w_t = F_L(K_t, L_t), \qquad v_t = F_K(K_t, L_t).$$

Now track one unit of goods saved by a young household at date \(t\). There are two ways to carry it to \(t+1\):

Asset bought at \(t\)Payoff at \(t+1\)
Bond (government debt or a private loan)\(1 + r_t\)
One unit of capital, installed for production at \(t+1\)rental \(v_{t+1}\) + undepreciated capital \(1-\delta\)

If both are held in equilibrium, no-arbitrage requires equal payoffs: \(1 + r_t = v_{t+1} + 1 - \delta\), i.e. \(v_{t+1} = r_t + \delta\). With \(L_{t+1}=1\):

Interest rate with capital III p.15
$$r_t = F_K(K_{t+1}, 1) - \delta .$$

The interest rate between \(t\) and \(t+1\) depends on next period's capital stock. That stock is exactly what today's young save.

This timing is what makes the equilibrium law of motion implicit (§5). Savers' return depends on how much they save in total.

3. Households

Generation \(t\) earns \(w_t\) when young, pays \(\tau^t_t\) when young and \(\tau^t_{t+1}\) when old, and saves \(s_t\):

$$s_t + c^t_t = w_t - \tau^t_t, \qquad c^t_{t+1} = (1+r_t)s_t - \tau^t_{t+1}.$$

Eliminating \(s_t\) gives the lifetime budget constraint III p.15:

$$c^t_t + \frac{c^t_{t+1}}{1+r_t} = w_t - \tau^t_t - \frac{\tau^t_{t+1}}{1+r_t} \;\equiv\; W_t .$$

Optimal saving depends on three things: the interest rate, first-period disposable income, and lifetime wealth \(W_t\). Alvarez writes

$$s_t = s\!\left(r_t,\; w_t - \tau^t_t,\; w_t - \tau^t_t - \frac{\tau^t_{t+1}}{1+r_t}\right).$$

The second argument matters because saving is disposable first-period income minus first-period consumption: \(s = (w-\tau^t_t) - c_y(r, W)\).

4. Walras' law with capital

With a government that issues assets \(B_t\) (\(B_t<0\) is debt) and buys \(g_t\), the government budget is \(B_t + g_t = (1+r_{t-1})B_{t-1} + \tau^t_t + \tau^{t-1}_t\), as in III p.3. Household saving now has two uses: lending to the government and holding capital.

Asset-market clearing is implied III p.16

If household budgets, the government budget and goods-market clearing hold at every date, and \(B_0 + s_0 = K_1\), then $$B_t + s_t = K_{t+1}\quad\text{for all } t\ge 1 .$$

Proof (the slides only assert this step)
  1. Add the two household budgets alive at \(t\). Young: \(s_t + c^t_t = w_t - \tau^t_t\). Old: \(c^{t-1}_t = (1+r_{t-1})s_{t-1} - \tau^{t-1}_t\). Summing, $$s_t + c^t_t + c^{t-1}_t = w_t + (1+r_{t-1})s_{t-1} - \tau^t_t - \tau^{t-1}_t .$$
  2. Use goods-market clearing. \(c^t_t + c^{t-1}_t = F(K_t,1) - g_t - K_{t+1} + (1-\delta)K_t\).
  3. Use constant returns (Euler's theorem). \(F(K_t,1) = w_t + v_t K_t = w_t + (r_{t-1}+\delta)K_t\). Output is exhausted by factor payments, so firms make zero profit. Substituting steps 2 and 3 into step 1, the \(w_t\) and \(\delta K_t\) terms cancel: $$s_t - K_{t+1} + \tau^t_t + \tau^{t-1}_t - g_t = (1+r_{t-1})(s_{t-1} - K_t).$$
  4. Add the government budget written as \(B_t - \tau^t_t - \tau^{t-1}_t + g_t = (1+r_{t-1})B_{t-1}\): $$\big(B_t + s_t - K_{t+1}\big) = (1+r_{t-1})\big(B_{t-1} + s_{t-1} - K_t\big).$$
  5. Induction. The term in brackets is zero at \(t=0\), so it is zero for all \(t\).
∎
Intuition

The young are the only savers. Whatever they don't lend to the government must end up as next period's capital. This is the same accounting as in Lesson 14, with \(K_{t+1}\) replacing zero on the right-hand side.

5. The equilibrium law of motion

With no taxes, government spending or debt (\(\tau=g=B=0\)), asset-market clearing becomes \(s_t = K_{t+1}\). Substituting factor prices III p.16:

$$K_{t+1} = s\big(F_K(K_{t+1},1) - \delta,\; F_L(K_t,1),\; F_L(K_t,1)\big).$$

Given \(K_1>0\), owned by the initial old, this equation pins down \(K_2\), then \(K_3\), and so on. It is implicit because \(K_{t+1}\) appears on both sides through \(r_t\). By the implicit function theorem it defines a map \(K_{t+1} = s^*(K_t)\) locally, provided

$$1 - s_r\,F_{KK}(K_{t+1},1) \neq 0 .$$

Since \(F_{KK}<0\), this holds automatically whenever saving is non-decreasing in \(r\) (\(s_r\ge 0\)). The slides' "local conditions in the problem set" amount to this denominator being positive.

6. Social security lowers saving, and (usually) capital

Introduce PAYG: \(\tau^t_t = \tau\), \(\tau^t_{t+1} = -\tau\). Each old person receives the tax paid by the one young person alive. Holding \(r_t\) and \(w_t\) fixed, lifetime wealth changes by III p.17

$$\frac{\partial W_t}{\partial \tau} = -\Big(1 - \frac{1}{1+r_t}\Big) = -\frac{r_t}{1+r_t} < 0 \quad\text{when } r_t>0 .$$

The household pays \(\tau\) today and gets back \(\tau\) tomorrow, which is a zero net return. Saving privately would have earned \(r_t>0\).

Claim: saving falls with \(\tau\)

If old-age consumption is a normal good and \(r_t>0\), then at fixed prices \(\partial s_t/\partial\tau < -\tfrac{1}{1+r_t} < 0\).

Proof
  1. From the old-age budget, \(c_o = (1+r)s + \tau\), so \(s = \dfrac{c_o(r,W) - \tau}{1+r}\).
  2. Differentiate: \(\dfrac{\partial s}{\partial\tau} = \dfrac{1}{1+r}\Big(\dfrac{\partial c_o}{\partial W}\dfrac{\partial W}{\partial\tau} - 1\Big)\).
  3. Normality gives \(\partial c_o/\partial W > 0\), and \(\partial W/\partial\tau = -r/(1+r)<0\), so the term in brackets is less than \(-1\). ∎

The economics: PAYG directly replaces private saving for retirement, since the transfer \(\tau\) arrives when old anyway, and the wealth loss reduces old-age consumption further. Both forces cut \(s\).

From saving to the capital stock

In general equilibrium, write the law of motion with the policy as \(K_{t+1} = s^*(K_t,\tau)\). Applying the implicit function theorem to \(K' - s\big(F_K(K',1)-\delta,\,\cdot\,\big) = 0\) gives

$$\frac{\partial s^*}{\partial\tau} = \frac{s_\tau}{1 - s_r F_{KK}} < 0,$$

using the claim and the positive denominator from §5. A steady state solves \(K^* = s^*(K^*,\tau)\). Differentiate both sides with respect to \(\tau\):

$$\frac{dK^*}{d\tau} = \frac{\partial s^*}{\partial K}\frac{dK^*}{d\tau} + \frac{\partial s^*}{\partial \tau} \quad\Longrightarrow\quad \boxed{\frac{dK^*}{d\tau} = \frac{\partial s^*/\partial\tau}{1 - \partial s^*/\partial K}} .$$
Steady-state comparative statics III p.17

Graphically, a higher \(\tau\) shifts the map \(s^*(\cdot,\tau)\) down. Where the map crosses the 45° line from above, the crossing moves left. Where it crosses from below, the crossing moves right. The figure below shows both cases at once.

Interactive: Cobb–Douglas law of motion \(K_{t+1} = (1-\alpha)K_t^\alpha - \tau\) (see §7). The blue curve is the map with the current \(\tau\); the dashed gray curve is \(\tau=0\). The orange staircase is the equilibrium path starting from \(K_1\). Try: raise \(\tau\) from 0. The upper, stable steady state moves left and a lower, unstable one appears and moves right. Then start \(K_1\) just below the unstable steady state: capital collapses, because the young cannot afford the tax.

7. A Cobb–Douglas example

Let \(F(K,L) = K^\alpha L^{1-\alpha}\) and suppose consumers care only about old-age consumption III p.18. Then the young save everything they have after tax, \(s_t = w_t - \tau\), and saving does not depend on \(r_t\). That makes the law of motion explicit:

  1. Wage. \(w_t = F_L(K_t,1) = (1-\alpha)K_t^\alpha\).
  2. Law of motion. \(K_{t+1} = s_t = (1-\alpha)K_t^\alpha - \tau\).
  3. Steady state without social security. \(K^* = (1-\alpha)K^{*\alpha}\), so \(K^{*\,1-\alpha} = 1-\alpha\) and $$K^* = (1-\alpha)^{1/(1-\alpha)} .$$ A fact used repeatedly below: \(K^{*\,\alpha-1} = \dfrac{1}{1-\alpha}\). Also \(w^* = (1-\alpha)K^{*\alpha} = K^*\), since the young save the whole wage.
  4. Stability. The slope of the map at \(K^*\) is \(\alpha(1-\alpha)K^{*\,\alpha-1} = \alpha\in(0,1)\), so \(K^*\) is stable.
  5. Steady-state interest rate. \(r^* = \alpha K^{*\,\alpha-1} - \delta = \dfrac{\alpha}{1-\alpha} - \delta\).

Introducing PAYG at \(K_1 = K^*\): who gains?

Generation 0 (initial old) owns \(K_1\), whose return is already fixed, and receives \(\tau\) from the young. It gains \(\tau\).

Generation 1 earns \(w_1 = K^*\), pays \(\tau\) and saves \(K_2 = K^* - \tau\). When old it receives the gross return on its capital plus the transfer from generation 2:

$$c^1_2(\tau) = (K^*-\tau)\big[1 - \delta + \alpha (K^*-\tau)^{\alpha-1}\big] + \tau .$$

Differentiate and evaluate at \(\tau=0\):

  1. Write \(K_2 = K^*-\tau\), so \(dK_2/d\tau=-1\), and \(c^1_2 = K_2\big[1-\delta+\alpha K_2^{\alpha-1}\big] + \tau\). By the product rule, \(\dfrac{d}{dK_2}\Big(K_2\big[1-\delta+\alpha K_2^{\alpha-1}\big]\Big) = 1-\delta+\alpha K_2^{\alpha-1} + \alpha(\alpha-1)K_2^{\alpha-1}\). Hence $$\frac{dc^1_2}{d\tau} = -\big[1-\delta+\alpha K_2^{\alpha-1}\big] - \alpha(\alpha-1)K_2^{\alpha-1} + 1 .$$
  2. Collect terms: \(= \delta - \alpha K_2^{\alpha-1} + \alpha(1-\alpha)K_2^{\alpha-1} = \delta - \alpha^2 K_2^{\alpha-1}\).
  3. At \(\tau=0\), \(K_2 = K^*\) and \(K^{*\,\alpha-1}=1/(1-\alpha)\): $$\boxed{\left.\frac{dc^1_2}{d\tau}\right|_{\tau=0} = \delta - \frac{\alpha^2}{1-\alpha}} .$$

So for \(\delta>0\), generation 1 gains when \(\alpha\) is small enough, namely when \(\alpha^2/(1-\alpha) < \delta\) III p.18.

Why can generation 1 gain? III p.19

In the pure-endowment economy, social security only reshuffles goods; nothing about production changes. With capital, taxing the young lowers \(K_2\), which raises the marginal product of capital \(\alpha K_2^{\alpha-1}\). Generation 1 is the owner of \(K_2\). It loses \(1+r\) per unit of foregone saving but gets \(\tau\) back from generation 2, and every remaining unit earns more. The term \(-\alpha(\alpha-1)K_2^{\alpha-1} = \alpha(1-\alpha)K_2^{\alpha-1}>0\) in step 1 is exactly this price effect. It is a pecuniary transfer from generation 2, whose wage \(w_2 = (1-\alpha)K_2^\alpha\) is lower.

But steady-state generations lose whenever \(r^*>0\)

Let \(K(\tau)\) be the stable steady state of \(K = (1-\alpha)K^\alpha - \tau\). A steady-state generation consumes \(c_{ss}(\tau) = K(\tau)\big[1-\delta+\alpha K(\tau)^{\alpha-1}\big] + \tau\).

  1. Implicit differentiation of the steady state at \(\tau=0\): \(K' = \alpha(1-\alpha)K^{\alpha-1}K' - 1 = \alpha K' - 1\), so \(K'(0) = -\dfrac{1}{1-\alpha}\).
  2. Differentiate \(c_{ss}\): \(c_{ss}' = \big[1-\delta+\alpha K^{\alpha-1} + \alpha(\alpha-1)K^{\alpha-1}\big]K' + 1 = \big[1+r^* - \alpha\big]K' + 1\), using \(\alpha(\alpha-1)K^{*\,\alpha-1}=-\alpha\).
  3. Substitute \(K'(0)\): \(c_{ss}'(0) = 1 - \dfrac{1 + r^* - \alpha}{1-\alpha} = \dfrac{(1-\alpha) - (1+r^*-\alpha)}{1-\alpha}\), so $$\boxed{c_{ss}'(0) = -\frac{r^*}{1-\alpha}} .$$

Steady-state generations gain from PAYG if and only if \(r^*<0\). That is the dynamic-inefficiency condition of Lesson 12, with no population growth. The gain to generation 1 is a transition effect. When \(r^*>0\), the CE has finite aggregate value and the First Welfare Theorem applies (Lesson 12). So no feasible reallocation, PAYG included, can make every generation better off: someone, here the generations far in the future, must lose III p.19.

Interactive: who gains from PAYG? Old-age consumption as a function of the tax \(\tau\), starting from \(K_1 = K^*\). Blue: generation 1, \(c^1_2(\tau)\). Orange: a generation in the new stable steady state, \(c_{ss}(\tau)\). Try: \(\alpha=0.2\), \(\delta=0.1\). Here \(r^*=0.15>0\), yet the blue curve rises at first while the orange curve falls. Then raise \(\delta\) above \(\alpha/(1-\alpha)\), so \(r^*<0\): now both rise, and PAYG is a Pareto improvement for small \(\tau\).

8. Check your understanding

1. Why does \(r_t\) depend on \(K_{t+1}\) rather than \(K_t\)?
  • Because the old own the capital stock at date t
  • Because saving at t becomes capital used at t+1
  • Because the wage at t depends only on capital K_t
  • Because depreciation happens before the production
A unit saved at \(t\) is installed and earns the rental \(v_{t+1} = F_K(K_{t+1},1)\) at \(t+1\), plus \(1-\delta\). No-arbitrage with bonds gives \(1+r_t = F_K(K_{t+1},1)+1-\delta\).
2. Which property of \(F\) is used to derive \(B_t + s_t = K_{t+1}\)?
  • Inada conditions at zero and infinity for capital
  • Strict concavity of F in capital, holding labour fixed
  • Constant returns, so factor payments exhaust output
  • A capital share that is constant over all of time
Euler's theorem \(F = w L + vK\) means there are no profits left over. With decreasing returns, profits would appear and someone would have to own the firms, adding a term to household budgets.
3. Raising \(\tau\) shifts the map \(s^*(\cdot,\tau)\) down. At a steady state where \(\partial s^*/\partial K > 1\), what happens?
  • K* rises, but that steady state is unstable anyway
  • K* falls, just as it does at the stable steady state
  • K* is unchanged because the slope exceeds one there
  • The steady state disappears for any positive τ value
\(dK^*/d\tau = s^*_\tau/(1-s^*_K)\). With \(s^*_\tau<0\) and \(s^*_K>1\), the denominator is negative, so \(dK^*/d\tau>0\). Visually, the map crosses the 45° line from below, so shifting it down moves the crossing right. Check the hollow point in the first figure.
4. In the Cobb–Douglas example with \(r^*>0\), generation 1 can gain from PAYG. Why is this consistent with the First Welfare Theorem?
  • Because the First Welfare Theorem fails with capital
  • Because generation 0 loses the transfer it receives
  • Because preferences in the example are not convex
  • Because later steady-state generations lose instead
With \(r^*>0\) the equilibrium is Pareto optimal, so PAYG cannot be a Pareto improvement. It helps generations 0 and 1 at the expense of the generations far in the future: \(c_{ss}'(0) = -r^*/(1-\alpha) < 0\).

9. Exercises

These follow the format of Alvarez's exams: true/false items with short justifications, then long derivations broken into small steps. Attempt each part before opening the solution.

Exercise 15.1 True or false? Justify. Exam format

For each statement, say whether it is true or false and give a justification of one to four lines.

  1. In the two-period Diamond OLG model with log utility and Cobb–Douglas technology, the competitive equilibrium path is necessarily Pareto optimal. Capital gives every generation a way to save without trading with other generations. (Past exam: Fall 2025 Final Q1.7, reworded)
    Show answer

    False. It depends on parameters. The steady-state interest rate is \(\bar r = \frac{\alpha}{\beta(1-\alpha)}-\delta\) (Exercise 15.2). If \(\bar r<0\), capital is above the golden rule, and permanently cutting \(K\) raises consumption at every date: a Pareto improvement. Capital does not open the missing markets between living and unborn generations. When \(\bar r<0\), the value of the aggregate endowment is again infinite (Lesson 12).

  2. In the Diamond model with \((1-\beta)\log c^t_t+\beta\log c^t_{t+1}\) and no government, a rise in the interest rate raises the saving of the young. (Past exam: Fall 2025 Final Q1.3, reworded)
    Show answer

    False. Saving is \(s_t=\beta w_t\), independent of \(r_t\). With log utility and no income when old, the income and substitution effects of \(r\) cancel exactly. This fails as soon as there is old-age income: with PAYG, \(s_t=\beta(w_t-\tau)-(1-\beta)\tau/(1+r_t)\), which does rise with \(r_t\) (Exercise 15.2(i)).

  3. In the same model, a higher level of TFP \(A\) raises steady-state capital and therefore lowers the steady-state interest rate. (Exam-inspired, Fall 2025 Final Q1)
    Show answer

    False. \(\bar K=[\beta(1-\alpha)A]^{1/(1-\alpha)}\) does rise with \(A\), but \(F_K(\bar K,1)=\alpha A\bar K^{\alpha-1}=\frac{\alpha}{\beta(1-\alpha)}\). Capital rises exactly enough to keep the marginal product unchanged, so \(\bar r\) does not depend on \(A\). Only preferences (\(\beta\)), the capital share (\(\alpha\)) and depreciation (\(\delta\)) decide whether the economy is dynamically inefficient.

  4. In the neoclassical growth model with an infinitely lived representative agent, if initial capital is so large that \(r(0)<0\), the equilibrium is not Pareto optimal. (Past exam: Fall 2025 Final Q4)
    Show answer

    False. The first part can happen: \(r(0)=f'(k_0)-\delta<0\) when \(k_0\) is large. But there is a single agent with finite wealth, so the value of aggregate consumption is finite, and the First Welfare Theorem applies. The agent simply runs capital down. A negative interest rate signals inefficiency only in combination with infinitely many agents and goods, as in OLG.

  5. Suppose the steady state without social security has \(\bar r>0\) and no population growth. Introducing PAYG cannot make every generation better off, but it can make both the initial old and generation 1 better off. (Problem set 2025 P3 Q6)
    Show answer

    True. With \(\bar r>0\) the equilibrium is Pareto optimal, so nobody can gain without someone losing. In the Cobb–Douglas example of §7, the initial old gain \(\tau\), and generation 1 gains whenever \(\delta>\alpha^2/(1-\alpha)\), through a higher return on scarcer capital. Steady-state generations lose: \(c_{ss}'(0)=-\bar r/(1-\alpha)<0\).

  6. Introducing PAYG social security always lowers steady-state capital. (Problem set 2025 P2 Q9–10)
    Show answer

    False. \(dK^*/d\tau = s^*_\tau/(1-s^*_K)\), with \(s^*_\tau<0\). At a stable steady state (\(0<s^*_K<1\)) capital falls. At an unstable one (\(s^*_K>1\)) the denominator is negative and the steady state rises. That case is never reached from nearby initial conditions, but the word "always" is wrong.

  7. In the OLG economy with capital, the condition \(B_t+s_t=K_{t+1}\) must be imposed as a separate equilibrium condition, in addition to goods-market clearing. (Exam-inspired, Problem set 2025 P2 Q4)
    Show answer

    False. It is implied by Walras' law. Add the young and old budgets and the government budget, then use goods-market clearing and \(F=w+vK\) (constant returns, or profits paid out). This gives \(B_t+s_t-K_{t+1}=(1+r_{t-1})(B_{t-1}+s_{t-1}-K_t)\), which is zero for all \(t\) once it is zero at the start (§4).

Exercise 15.2 The Diamond model Past exam: Fall 2025 Final Q1 (70 points + extensions)

Consider a two-period OLG economy with no heterogeneity. Generation \(t\) has utility \((1-\beta)\log c^t_t+\beta\log c^t_{t+1}\). Each generation has one unit of labour, supplied inelastically when young, and each cohort has size one. The initial old own the capital stock \(K_1>0\). Capital evolves as \(K_{t+1}=I_t+(1-\delta)K_t\), and feasibility is \(I_t+c^t_t+c^{t-1}_t=F(K_t,L_t)\) with \(F(K,L)=AK^\alpha L^{1-\alpha}\), \(A>0\), \(\alpha\in(0,1)\). Firms hire labour at wage \(w_t\) and rent capital at rental rate \(v_t\). Young agents face \(c^t_t+s_t=w_t\) and, when old, \(c^t_{t+1}=s_t(1+r_t)\).

  1. [10] What are the first-order conditions of the firm's problem? Your answer should be two equations.
  2. [10] What is the equilibrium value of \(L_t\)? Your answer is one number.
  3. [10] Find the young's optimal saving as a function of \(w_t\) and \(\beta\). You should get an explicit, simple expression.
  4. [10] In equilibrium, what is the relationship between \(r_t\), \(v_{t+1}\) and \(\delta\)? One line.
  5. [10] By Walras' law, what is the relationship between \(s_t\) and \(K_{t+1}\)? One line.
  6. [10] Combine your answers into a first-order difference equation for capital. One equation.
  7. [10] Is the equilibrium path necessarily Pareto optimal, or does it depend on parameters? (On the exam, no justification was required. Here, find the condition on parameters.)
  8. [extension] Let the cohort born at \(t\) have size \((1+n)^t\). Writing \(k\) for capital per young worker, find the steady-state \(\bar r\) and the condition for dynamic inefficiency. Show that with \(\delta=1\) the condition does not depend on \(n\).
  9. [extension] Back to \(n=0\). Introduce PAYG: each young pays \(\tau\), each old receives \(\tau\). Show that saving now depends on \(r_t\), and write the (implicit) law of motion for capital.
Hint for (g)

Compute \(F_K\) at the steady state from (f). With no population growth, steady-state consumption is \(F(K,1)-\delta K\). Ask what happens to it if \(K\) is permanently reduced.

Show solution

(a) The firm maximizes \(F(K,L)-v_tK-w_tL\): \(\;v_t=\alpha AK_t^{\alpha-1}L_t^{1-\alpha}\) and \(w_t=(1-\alpha)AK_t^{\alpha}L_t^{-\alpha}\).

(b) \(L_t=1\): one cohort of size one supplies one unit each.

(c) Maximize \((1-\beta)\log(w_t-s_t)+\beta\log[s_t(1+r_t)]\). The FOC \(\frac{1-\beta}{w_t-s_t}=\frac{\beta}{s_t}\) gives \(s_t=\beta w_t\). The \(1+r_t\) term drops out because it enters \(\log c^t_{t+1}\) additively.

(d) No arbitrage between bonds and capital: \(1+r_t=v_{t+1}+1-\delta\). Note the date: the rental rate is earned at \(t+1\), when the capital saved at \(t\) is used.

(e) \(s_t=K_{t+1}\). The young are the only savers and there are no government bonds, so their saving is next period's capital (§4 with \(B\equiv0\)).

(f) \(K_{t+1}=\beta w_t=\beta(1-\alpha)AK_t^{\alpha}\). The map is concave, infinitely steep at 0, and crosses the 45° line once, at \(\bar K=[\beta(1-\alpha)A]^{1/(1-\alpha)}\). Its slope there is \(\alpha<1\), so the path converges monotonically from any \(K_1>0\).

(g) It depends on parameters. At the steady state, \(A\bar K^{\alpha-1}=1/(\beta(1-\alpha))\), so $$\bar r=F_K(\bar K,1)-\delta=\frac{\alpha}{\beta(1-\alpha)}-\delta .$$ If \(\bar r\ge0\), the steady state is efficient. If \(\bar r<0\), i.e. \(\alpha\lt \delta\beta(1-\alpha)\), it is dynamically inefficient. To see this, at some date \(T\) cut \(K_{T+1}\) permanently by a small \(\varepsilon\). Consumption at \(T\) rises by \(\varepsilon\). At every later date, steady-state consumption \(F(K,1)-\delta K\) changes by \(-(F_K-\delta)\varepsilon=-\bar r\varepsilon>0\). Total consumption is higher at every date from \(T\) on. Hand the extra to the old at each date, so every generation from \(T-1\) on gains and no one loses.

On the official solution. The official answer explains the failure of the First Welfare Theorem by "missing markets between generations". The sharper statement, as in Lesson 12, is that when \(\bar r<0\) the prices \(p_t\) do not fall, so the value of the aggregate endowment is infinite. Some student review notes describe the endowment OLG inefficiency as "over-accumulation of capital". That language is right only here, where there is capital.

(h) Let cohort size be \(N_t=(1+n)^t\). Then \(K_{t+1}=N_ts_t\), so per-worker capital satisfies \((1+n)k_{t+1}=\beta(1-\alpha)Ak_t^\alpha\). At the steady state \(A\bar k^{\alpha-1}=\frac{1+n}{\beta(1-\alpha)}\), so \(\bar r=\frac{\alpha(1+n)}{\beta(1-\alpha)}-\delta\). The golden rule maximizes \(f(k)-(n+\delta)k\), i.e. \(r=n\). So the economy is inefficient iff \(\bar r<n\), i.e. \(\frac{\alpha(1+n)}{\beta(1-\alpha)}<1+n-(1-\delta)\). With \(\delta=1\), this is \(\alpha(1+n)\lt \beta(1-\alpha)(1+n)\), i.e. \(\alpha\lt \beta(1-\alpha)\), whatever \(n\) is.

(i) Lifetime wealth is \(W_t=w_t-\tau+\frac{\tau}{1+r_t}\), and log utility gives \(c^t_t=(1-\beta)W_t\). So $$s_t=(w_t-\tau)-c^t_t=\beta(w_t-\tau)-\frac{(1-\beta)\tau}{1+r_t},$$ which is increasing in \(r_t\): a higher \(r\) lowers the present value of the transfer, so the young must save more. Using \(1+r_t=\alpha AK_{t+1}^{\alpha-1}+1-\delta\) and \(s_t=K_{t+1}\), $$K_{t+1}=\beta\big[(1-\alpha)AK_t^\alpha-\tau\big]-\frac{(1-\beta)\tau}{1-\delta+\alpha AK_{t+1}^{\alpha-1}} .$$ \(K_{t+1}\) appears on both sides: this is the implicit law of motion of §5.

Exercise 15.3 Social security and capital accumulation Problem set 2025 P2

Generation \(t\) has a general utility \(u(c^t_t,c^t_{t+1})\), works one unit when young, and faces \(c^t_t+s_t=w_t-\tau^t_t\) and \(c^t_{t+1}=s_t(1+r_t)-\tau^t_{t+1}\). Technology \(F\) has constant returns with \(F_{KK}<0\), and capital depreciates at rate \(\delta\). There is no government spending or debt (\(g_t=0\), \(B_t=0\)). PAYG is \(\tau^t_t=\tau\), \(\tau^t_{t+1}=-\tau\), and assume \(r_t>0\).

  1. [10] Argue that no arbitrage implies \(r_t=F_K(K_{t+1},1)-\delta\). Be careful with the date at which \(F_K\) is evaluated.
  2. [10] Argue that optimal saving can be written \(s_t=s\big(r_t,\;w_t-\tau^t_t,\;w_t-\tau^t_t-\tau^t_{t+1}/(1+r_t)\big)\).
  3. [15] Show, without using derivatives, that if old-age consumption is not inferior then saving is strictly decreasing in \(\tau\) at fixed \(r_t,w_t\). Hint: compare \(\tau'>\tau\). In the worst case the income effect on \(c^t_t\) is bounded by \(-(\tau'-\tau)\frac{r_t}{1+r_t}\).
  4. [15] Suppose \(\partial s/\partial r>0\) at \(\tau=0\). Use the implicit function theorem to show that there is a function \(s^*\) with \(K_{t+1}=s^*(K_t,\tau)\) near \(\tau=0\).
  5. [15] Show that \(\partial s^*/\partial\tau<0\) at \(\tau=0\). Hint: use (c) for the direct effect, then sign the indirect effect through the interest rate.
  6. [10] Assume \(0\lt \partial s^*/\partial K<1\) near the no-social-security steady state \(K^*>0\). Show that a small \(\tau>0\) lowers steady-state capital. A graph suffices.
  7. [10] If instead \(\partial s^*/\partial K>1\) near \(K^*\), show that steady-state capital is higher with social security. Is that steady state stable?
Show solution

(a) A unit saved at \(t\) can buy a bond paying \(1+r_t\) at \(t+1\), or a unit of capital that is used at \(t+1\). The capital earns the rental \(v_{t+1}=F_K(K_{t+1},1)\) plus the undepreciated \(1-\delta\). If both are held, the payoffs must be equal: \(r_t=F_K(K_{t+1},1)-\delta\). The capital stock is \(K_{t+1}\), not \(K_t\). Both 2025 solution sets slip on this index.

(b) The FOC is \(u_1/u_2=1+r_t\). Together with the lifetime budget \(c^t_t+\frac{c^t_{t+1}}{1+r_t}=W_t\equiv w_t-\tau^t_t-\frac{\tau^t_{t+1}}{1+r_t}\), it determines \(c^t_t=c_y(r_t,W_t)\). Then \(s_t=(w_t-\tau^t_t)-c_y(r_t,W_t)\), a function of the three listed arguments.

(c) With \(\tau^t_{t+1}=-\tau\), \(W=w-\frac{r}{1+r}\tau\). Raising the tax from \(\tau\) to \(\tau'\) changes wealth by \(\Delta W=-\frac{r}{1+r}(\tau'-\tau)<0\), using \(r>0\). Differencing the lifetime budget, \(\Delta c_y+\frac{\Delta c_o}{1+r}=\Delta W\). Since \(c_o\) is not inferior and \(\Delta W<0\), \(\Delta c_o\le0\), so \(\Delta c_y\ge\Delta W\). Then $$\Delta s=-(\tau'-\tau)-\Delta c_y\le-(\tau'-\tau)+\tfrac{r}{1+r}(\tau'-\tau)=-\tfrac{\tau'-\tau}{1+r}<0 .$$ Each unit of tax lowers saving by at least \(1/(1+r)\).

(d) Define \(\phi(K',K,\tau)=K'-s\big(F_K(K',1)-\delta,\;F_L(K,1)-\tau,\;F_L(K,1)-\tau+\tfrac{\tau}{1+F_K(K',1)-\delta}\big)\). An equilibrium has \(\phi=0\). At \(\tau=0\), \(\partial\phi/\partial K'=1-s_1F_{KK}\), where \(s_1\) is the derivative with respect to \(r\). This is strictly positive because \(s_1>0\) and \(F_{KK}<0\). By the implicit function theorem, \(\phi=0\) defines \(K'=s^*(K,\tau)\) locally. Wording note: the problem set says this assumption means "the substitution effect is not strong enough". In fact \(\partial s/\partial r>0\) means the substitution effect dominates the income effect.

(e) Differentiate \(\phi=0\) with respect to \(\tau\) at \(\tau=0\). The terms in \(\tau\,dr/d\tau\) vanish, leaving $$\frac{\partial s^*}{\partial\tau}=\frac{-s_2-s_3\frac{r}{1+r}}{1-s_1F_{KK}}=\frac{\partial s/\partial\tau\big|_{r\text{ fixed}}}{1-s_1F_{KK}}<0 .$$ The numerator is negative by (c), the denominator positive by (d). The indirect effect works through the interest rate: lower \(K_{t+1}\) raises \(r_t\), which raises saving since \(s_1>0\). That dampens the fall but cannot reverse it. Watch the sign of the \(s_3\) term: \(\frac{\partial}{\partial\tau}\big(-\tau+\frac{\tau}{1+r}\big)=-\frac{r}{1+r}\). One 2025 solution set writes \(+s_3\frac{r}{1+r}\).

(f) Differentiate \(K^*=s^*(K^*,\tau)\): \(\frac{dK^*}{d\tau}=\frac{s^*_\tau}{1-s^*_K}<0\). Graphically, the map shifts down, and since it crosses the 45° line from above, the crossing moves left.

(g) Now \(1-s^*_K<0\), so \(dK^*/d\tau>0\): the map crosses from below and shifting it down moves the crossing right. But a steady state with slope above one is unstable, since deviations grow. The perverse comparative static applies only at a steady state the economy would never settle in. You can see both cases in the first figure of this lesson.

Exercise 15.4 Generation 1 can gain from social security Problem set 2025 P3

Modify the model of Exercise 15.3: \(F(K,L)=K^\alpha L^{1-\alpha}\), utility is \(c^t_{t+1}\) (only old-age consumption matters), and \(g_t=B_t=0\). The economy starts at the no-social-security steady state \(K_1=K^*\). At date 1, PAYG \((\tau,-\tau)\) is announced.

  1. [5] Show that \(s_t=w_t-\tau^t_t\) and that \(K_{t+1}=(1-\alpha)K_t^\alpha-\tau^t_t\).
  2. [5] Find the steady state \(K^*\) without social security, and show \(K^{*\,\alpha-1}=1/(1-\alpha)\) and \(r^*=\frac{\alpha}{1-\alpha}-\delta\).
  3. [10] Show that \(c^1_2(\tau)=(K^*-\tau)\big[1-\delta+\alpha(K^*-\tau)^{\alpha-1}\big]+\tau\). Why doesn't generation 1's wage depend on \(\tau\)?
  4. [10] Show that \(\frac{dc^1_2}{d\tau}\big|_{\tau=0}=\delta-\frac{\alpha^2}{1-\alpha}\), and find the range of \(\alpha\) for which generation 1 gains.
  5. [10] The point of the example is that generation 1 can gain even though the interest rate is positive. Show that this requires \(\frac{\alpha^2}{1-\alpha}\lt \delta\lt \frac{\alpha}{1-\alpha}\), and that such a \(\delta\) exists for every \(\alpha\in(0,1)\).
  6. [10] Is it possible that every generation is made better off? Hint: the First Welfare Theorem holds in equilibria with positive interest rates. Then confirm it directly by showing \(c_{ss}'(0)=-r^*/(1-\alpha)\) for steady-state generations.
  7. [10] Explain the economics: why can generation 1 gain here, when in the endowment economy every generation after the initial old loses whenever \(r>0\)?
Show solution

(a) Young-age consumption is worthless to the agent, so it saves everything after tax: \(s_t=w_t-\tau^t_t\). With \(B_t=0\), \(K_{t+1}=s_t\), and \(w_t=F_L(K_t,1)=(1-\alpha)K_t^\alpha\).

(b) \(K^*=(1-\alpha)K^{*\alpha}\) gives \(K^*=(1-\alpha)^{1/(1-\alpha)}\) and \(K^{*\,\alpha-1}=1/(1-\alpha)\). Then \(r^*=\alpha K^{*\,\alpha-1}-\delta=\frac{\alpha}{1-\alpha}-\delta\).

(c) \(K_1=K^*\) is predetermined, so \(w_1=(1-\alpha)K^{*\alpha}=K^*\) regardless of \(\tau\). Generation 1 saves \(K_2=K^*-\tau\), earns \(1+r_1=1-\delta+\alpha K_2^{\alpha-1}\) on it, and receives \(\tau\) from generation 2.

(d) Write \(c^1_2=(1-\delta)K_2+\alpha K_2^\alpha+\tau\) with \(dK_2/d\tau=-1\). Then \(\frac{dc^1_2}{d\tau}=-(1-\delta)-\alpha^2K_2^{\alpha-1}+1=\delta-\alpha^2K_2^{\alpha-1}\). At \(\tau=0\) this is \(\delta-\frac{\alpha^2}{1-\alpha}\). It is positive iff \(\alpha^2+\delta\alpha-\delta<0\), i.e. \(\alpha\lt \hat\alpha=\frac{-\delta+\sqrt{\delta^2+4\delta}}{2}\).

(e) We need \(\delta>\alpha^2/(1-\alpha)\) for the gain and \(r^*>0\iff\delta\lt \alpha/(1-\alpha)\). The interval is non-empty because \(\alpha^2\lt \alpha\). Note: neither 2025 solution set checks this. "Small enough \(\alpha\)" alone is not sufficient: as \(\alpha\to0\), \(r^*\to-\delta<0\), and the example slides into the dynamically inefficient case, where a gain is no surprise.

(f) No. With \(r^*>0\) the pre-reform equilibrium is Pareto optimal, so a gain for some generations must be paid for by losses elsewhere. Directly, differentiate the steady state \(K=(1-\alpha)K^\alpha-\tau\): \(K'(0)=-1/(1-\alpha)\). Steady-state consumption is \(c_{ss}=K(1-\delta)+\alpha K^\alpha+\tau\), so $$c_{ss}'(0)=\big[1-\delta+\alpha^2K^{*\,\alpha-1}\big]K'(0)+1=1-\frac{1-\delta+\alpha^2/(1-\alpha)}{1-\alpha}=\frac{\delta-\alpha/(1-\alpha)}{1-\alpha}=-\frac{r^*}{1-\alpha}<0 .$$

(g) Generation 1's principal is returned exactly by the transfer, so only the return on its smaller saving changes. Taxing the young lowers \(K_2\), which raises \(F_K\). Generation 1's wage is already fixed, so it captures the higher return without bearing the lower wage. The cost falls on generation 2, whose wage \((1-\alpha)K_2^\alpha\) is lower. This is a general-equilibrium price effect. It cannot arise in the endowment economy, where social security moves goods but changes no productive opportunity.

Exercise 15.5 Owning capital directly Slides III p.15

Suppose households own capital directly, rent it to firms, and sell the undepreciated stock to the next young generation. Show that the return on this strategy equals \(F_K(K_{t+1},1)+1-\delta\). Conclude that if the government also issued bonds paying \(1+r_t>F_K(K_{t+1},1)+1-\delta\), no one would hold capital. What would that imply for \(K_{t+1}\) and for \(F_K\)?

Show solution

Buy one unit of capital at \(t\). At \(t+1\), rent it for \(v_{t+1}=F_K(K_{t+1},1)\), then sell the \(1-\delta\) that remains. Installed capital and goods trade one for one. The gross return is \(F_K(K_{t+1},1)+1-\delta\). If bonds paid strictly more, every saver would hold only bonds and \(K_{t+1}=0\). But then \(F_K(0,1)=\infty\) under Inada conditions, which contradicts the inequality. So in an equilibrium with \(K_{t+1}>0\) the returns must be equal, which is the content of \(v_{t+1}=r_t+\delta\).

Exercise 15.6 Walras' law without constant returns Proof

Redo the Walras' law argument of §4 when \(F\) has decreasing returns, with profits \(\pi_t=F(K_t,1)-w_t-v_tK_t>0\) paid to the young. Show that the conclusion \(B_t+s_t=K_{t+1}\) survives once household budgets include \(\pi_t\).

Show solution

The young budget becomes \(s_t+c^t_t=w_t+\pi_t-\tau^t_t\). In step 3, \(F(K_t,1)=w_t+\pi_t+(r_{t-1}+\delta)K_t\). The extra \(\pi_t\) appears on both sides and cancels. Everything else is unchanged, so the same recursion and induction apply. Walras' law needs every unit of output to be someone's income, which is the role of \(\sum_i\theta^i_j=1\) in Lesson 2.

Exercise 15.7 Saving and PAYG when \(r<0\) Slides III p.17

The claim in §6 assumed \(r_t>0\). Suppose instead \(r_t<0\), so PAYG raises lifetime wealth. Show that if both \(c_y\) and \(c_o\) are normal, saving still falls with \(\tau\) at fixed prices.

Hint

From the lifetime budget \(c_y+c_o/(1+r)=W\), normality of \(c_y\) gives \(\partial c_o/\partial W\le1+r\).

Show solution

Again \(\partial s/\partial\tau=\frac{1}{1+r}\big(c_{o,W}\cdot(-\tfrac{r}{1+r})-1\big)\). With \(r<0\) the first term is positive, but \(c_{o,W}\le1+r\) implies \(c_{o,W}\cdot\frac{-r}{1+r}\le-r\). So the bracket is at most \(-r-1=-(1+r)<0\), and saving falls. The transfer received when old replaces private saving one for one; the wealth effect can offset only part of that.

Key takeaways

💬 Stuck or curious? Ask me (your Claude teacher) anything. Try "redo the Cobb–Douglas example with log utility instead of old-age-only utility" or "why does the unstable steady state move the 'wrong' way?"
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