Theory of Income · Part V: Aggregation & the Social Planner · Lesson 23 of 25

Negishi Weights: the Welfare Theorems via First-Order Conditions

Covers Class Note 3, slides 18–25 · About 40 min · Prerequisites: Lesson 22 (planner FOCs), Lesson 4 and Lesson 6 (the general welfare theorems)
By the end you can:
  1. write the household's Kuhn–Tucker conditions and prove that the budget multiplier \(\mu_i\) is the marginal utility of income;
  2. prove both welfare theorems for a smooth exchange economy by matching the household's FOCs to the planner's: \(\lambda_i=\kappa/\mu_i\), \(\gamma=\kappa p\);
  3. say exactly which assumptions this proof uses that the general proofs of Lessons 4 and 6 do not;
  4. explain why rich agents get large Pareto weights, and why equilibrium prices depend on the wealth distribution in general;
  5. compute a competitive equilibrium with Negishi's method: guess weights, solve the planner, check budgets, update the weights.
Primary source Alvarez, Class Note 3, slides 18–25. For a textbook treatment of the FOC characterization of Pareto optima and its link to prices: Mas-Colell, Whinston & Green, Microeconomic Theory, §16.E (Pareto optimality and social welfare optima) and §16.F (first-order conditions for Pareto optimality); §3.D for the multiplier as the marginal utility of wealth. The original idea is T. Negishi (1960), "Welfare economics and existence of an equilibrium for a competitive economy," Metroeconomica 12, 92–97. Ljungqvist & Sargent, Recursive Macroeconomic Theory, use Negishi's algorithm to compute equilibria in their chapters on complete-markets economies.
Notation for this lesson

1. Where we are

Lesson 21 showed that, with concave utilities, every Pareto optimum solves a weighted planner problem $$W:\quad \max_{\{x^i\}}\ \sum_{i\in I}\lambda_i\,u^i(x^i)\quad\text{s.t.}\quad \sum_{i\in I}x^i\le\bar e,$$ and Lesson 22 wrote its first-order conditions for an interior solution with \(\lambda\gg0\) CN3 p.16: $$\lambda_i\,\frac{\partial u^i(\bar x^i)}{\partial x_l}=\gamma_l\qquad\text{for all goods }l\text{ and agents }i. \tag{2}$$ Two consequences: every agent's MRS equals \(\gamma_l/\gamma_k\) (the weights drop out), and the weights fix levels: \(u^i_l/u^j_l=\lambda_j/\lambda_i\). This lesson does the same exercise for the market and lines the two up. The punchline is one sentence: a competitive equilibrium is a planner's optimum in which each agent's weight is the inverse of her marginal utility of income, and the shadow values are the prices.

2. The household side: \(\mu_i\) is the marginal utility of income

In a pure exchange economy, household \(i\) solves $$\max_{x\in X^i}\ u^i(x)\quad\text{s.t.}\quad p\cdot x\le p\cdot e^i .$$ Under assumptions HH and CC (convex \(X^i\), concave \(u^i\)), an interior solution \(\bar x^i\) is characterized by CN3 p.18 $$\frac{\partial u^i(\bar x^i)}{\partial x_l}=\mu_i\,p_l\qquad\text{for all }l, \tag{3}$$ together with \(\mu_i\ge0\) and complementary slackness \(\mu_i\,(p\cdot e^i-p\cdot\bar x^i)=0\).

Claim: \(\mu_i\) is the marginal utility of income CN3 p.18

Let \(V^i(p,w)=\max\{u^i(x): p\cdot x\le w\}\) be the indirect utility function and \(x^*(p,w)\) the (differentiable, interior) demand. Then \(\displaystyle\frac{\partial V^i(p,w)}{\partial w}=\mu_i\). Moreover, if \(u^i\) is concave then \(V^i\) is concave in \(w\), so \(\mu_i\) is non-increasing in wealth.

Proof (filling in the slide's "from the envelope theorem")
  1. Write the value. The budget binds, so \(V^i(p,w)=u^i(x^*(p,w))\) with \(p\cdot x^*(p,w)=w\) for all \(w\).
  2. Differentiate the value. By the chain rule, \(\partial V^i/\partial w=\sum_l u^i_l\,\partial x^*_l/\partial w\).
  3. Use the FOC (3). Replace \(u^i_l\) by \(\mu_ip_l\): \(\partial V^i/\partial w=\mu_i\sum_l p_l\,\partial x^*_l/\partial w\).
  4. Differentiate the budget identity. Differentiating \(p\cdot x^*(p,w)=w\) in \(w\) gives \(\sum_lp_l\,\partial x^*_l/\partial w=1\): an extra dollar is all spent. Hence \(\partial V^i/\partial w=\mu_i\).
  5. Concavity of \(V^i\) in \(w\). Take wealth levels \(w,w'\), optimal bundles \(x,x'\), and \(t\in(0,1)\). The bundle \(tx+(1-t)x'\) costs \(tw+(1-t)w'\), so it is affordable at that wealth, and it lies in the convex set \(X^i\). Concavity of \(u^i\) gives \(V^i(p,tw+(1-t)w')\ge u^i(tx+(1-t)x')\ge tV^i(p,w)+(1-t)V^i(p,w')\).
  6. Conclude. A concave differentiable function has a non-increasing derivative, so \(\mu_i=\partial V^i/\partial w\) falls (weakly) as \(w\) rises.
∎
Intuition: one budget, one multiplier

Divide (3) by \(p_l\): \(u^i_l/p_l=\mu_i\) for every good. At an optimum, the last dollar spent on any good buys the same utility, and that common "utility per dollar" is \(\mu_i\). It is agent-specific but not good-specific, because each agent faces one budget. A rich agent with concave utility is already consuming a lot, so her last dollar buys little extra utility: low \(\mu_i\).

\(\mu_i\) is cardinal, so the weights are too

Replace \(u^i\) by \(2u^i\): preferences, demands and the equilibrium are unchanged, but every \(u^i_l\) doubles, so \(\mu_i\) doubles and the weight \(1/\mu_i\) halves. Pareto weights are only meaningful relative to a chosen utility representation. Comparing \(\mu_i\) across agents ("the rich have low \(\mu\)") is unambiguous only when agents share the same \(u\); otherwise the comparison depends on how each \(u^i\) is scaled. (Lesson 21 showed that concavity itself is a cardinal property.)

Two sets of first-order conditions, side by side

Dividing (3) for goods \(l\) and \(k\), and comparing two agents for the same good CN3 p.19:

Planner problem \(W\)Competitive equilibrium
FOC\(\lambda_i\,u^i_l=\gamma_l\)\(u^i_l=\mu_i\,p_l\)
Efficiency (MRS)\(\dfrac{u^i_l}{u^i_k}=\dfrac{\gamma_l}{\gamma_k}\) for all \(i\)\(\dfrac{u^i_l}{u^i_k}=\dfrac{p_l}{p_k}\) for all \(i\)
Distribution (levels)\(\dfrac{u^i_l}{u^j_l}=\dfrac{\lambda_j}{\lambda_i}\)\(\dfrac{u^i_l}{u^j_l}=\dfrac{\mu_i}{\mu_j}\)
What sets the levelsthe weights \(\lambda\)the wealth distribution \(\{p\cdot e^i\}\), through \(\mu\)

The MRS rows contain neither \(\lambda\) nor \(\mu\): both problems equalize marginal rates of substitution, which is the "efficiency" part. The level rows say the two problems pick the same point on the contract curve exactly when \(\lambda_j/\lambda_i=\mu_i/\mu_j\), i.e. \(\lambda_i\propto1/\mu_i\). (A circulating review sheet prints the planner's distribution row as \(\lambda_i/\lambda_j\); that is upside down. From (2), \(u^i_l=\gamma_l/\lambda_i\), so a higher weight means a lower marginal utility.)

3. The First Welfare Theorem via FOCs

Theorem (1WT, smooth version) CN3 pp.20–21

In a pure exchange economy with HH and CC, let \((p,\{\bar x^i\})\) be a CE in which each \(\bar x^i\) is interior and each \(u^i\) is differentiable and strictly increasing. Then \(\{\bar x^i\}\) solves the planner problem \(W\) with weights and multipliers $$\lambda_i=\frac{\kappa}{\mu_i},\qquad \gamma_l=\kappa\,p_l,\qquad\text{for any }\kappa>0,$$ and is therefore Pareto optimal.

Proof
  1. Household FOCs hold. Each \(\bar x^i\) is an interior maximizer, so (3) holds: \(u^i_l(\bar x^i)=\mu_ip_l\) for all \(l\). Since \(u^i_l>0\), we have \(\mu_i>0\) and \(p_l>0\).
  2. Divide by \(\mu_i\). \(\frac{1}{\mu_i}u^i_l(\bar x^i)=p_l\) for all \(i,l\). The right side is the same for every agent CN3 p.21.
  3. Rename. Multiply by any \(\kappa>0\) and set \(\lambda_i=\kappa/\mu_i\), \(\gamma_l=\kappa p_l\). Then \(\lambda_iu^i_l(\bar x^i)=\gamma_l\): this is exactly the planner's condition (2). Both \(\lambda\gg0\) and \(\gamma\gg0\).
  4. Feasibility and complementary slackness. Markets clear, \(\sum_i\bar x^i=\bar e\), so the resource constraints hold with equality, as complementary slackness requires when \(\gamma_l>0\).
  5. Sufficiency of the planner's FOCs. The planner's Lagrangian \(\sum_i\lambda_iu^i(x^i)+\sum_l\gamma_l\big(\bar e_l-\sum_ix^i_l\big)\) is concave in \(\{x^i\}\) (CC, \(\lambda\gg0\), linear constraint terms). Its gradient is zero at \(\{\bar x^i\}\), so \(\{\bar x^i\}\) maximizes the Lagrangian; with feasibility and complementary slackness, it maximizes \(W\).
  6. Strictly positive weights give PO. By the sufficiency half of the theorem in Lesson 21: if a feasible allocation Pareto-dominated \(\{\bar x^i\}\), it would raise \(\sum_i\lambda_iu^i\) because every \(\lambda_i>0\). Contradiction.
∎

The constant \(\kappa\) reflects two harmless normalizations: prices are only defined up to scale (Lesson 2), and so is the planner's objective. A convenient choice is \(\kappa\) such that \(\sum_i\lambda_i=1\).

This proof needs much more than the proof in Lesson 4
General 1WT (Lesson 4)1WT via FOCs (this lesson)
Preferenceslocal non-satiation onlydifferentiable, strictly increasing, concave (CC)
Consumption setsanythingconvex (HH); solution interior
Productionallowed, any \(Y^j\)none (pure exchange)
Value of the endowmentfinite (finitely many goods, or \(\sum p_t\bar e_t\lt\infty\))finitely many goods
What you getCE is POCE is PO and the weights \(\lambda_i=\kappa/\mu_i\)

So the FOC proof is a weaker theorem. If utility is not concave, the planner's FOCs are no longer sufficient and Step 5 breaks; but the CE is still PO, by Lesson 4. What breaks is this proof, not the result. The payoff of the FOC route is the explicit dictionary between market objects \((p,\mu)\) and planner objects \((\gamma,\lambda)\).

Reading the dictionary CN3 p.22

4. The Second Welfare Theorem via FOCs

Theorem (2WT, smooth version) CN3 pp.23–24

In a pure exchange economy with HH and CC, let \(\{\bar x^i\}\) be an interior Pareto optimum that solves \(W\) for weights \(\lambda\gg0\), with differentiable, strictly increasing \(u^i\). Set $$p=\gamma,\qquad \mu_i=\frac{1}{\lambda_i},\qquad e^i=\bar x^i .$$ Then \((p,\{\bar x^i\})\) is a competitive equilibrium for the endowments \(\{e^i\}\).

Proof
  1. Planner FOCs hold. \(\{\bar x^i\}\) solves \(W\) at an interior point, and the constraints are linear, so the necessary conditions (2) hold for some \(\gamma\ge0\): \(\lambda_iu^i_l(\bar x^i)=\gamma_l\).
  2. Shadow values are positive. \(\lambda_i>0\) and \(u^i_l>0\) give \(\gamma_l>0\) for every good.
  3. Define prices and multipliers. Let \(p=\gamma\) and \(\mu_i=1/\lambda_i>0\). Dividing (2) by \(\lambda_i\): \(u^i_l(\bar x^i)=\mu_ip_l\). This is the household FOC (3) CN3 p.24.
  4. Choose endowments. Give each agent \(e^i=\bar x^i\). Then \(p\cdot\bar x^i=p\cdot e^i\): the bundle is affordable and the budget binds, so complementary slackness holds with \(\mu_i>0\).
  5. Sufficiency of the household's FOCs. \(u^i\) is concave and the budget linear, so (3) plus complementary slackness are sufficient: \(\bar x^i\) maximizes \(u^i\) over \(i\)'s budget set.
  6. Markets clear. \(\sum_i\bar x^i=\bar e=\sum_ie^i\), since the PO allocation is feasible. Every CE condition holds. ∎
Compare with the separating-hyperplane proof (Lesson 6)

Lesson 6 needed only convexity (HH, FF) and LNS, allowed production and non-differentiable utility, and found the price as the normal of a hyperplane separating "better" bundles from feasible ones. It delivered only a quasi-equilibrium, and Arrow's cheapest-point problem had to be ruled out separately (Lesson 7). Here the gradient \(\gamma\) of the planner's problem is that normal, and interiority with \(p\gg0\) means no agent sits at a cheapest point, so the quasi-equilibrium caveat disappears. The price paid: differentiability, concavity, interiority, \(\lambda\gg0\), and no production.

5. Prices depend on the income distribution

In general, the equilibrium price \(p\) and the allocation \(\{\bar x^i\}\) depend on the distribution of endowments \(\{e^i\}\); equivalently, the shadow values \(\gamma\) and the PO allocation depend on the weights \(\lambda\) CN3 p.25. The reason is simple. Moving wealth from one agent to another changes aggregate demand unless both spend the marginal dollar in the same way. If A likes good 1 more than B does, giving A more wealth raises the demand for good 1 and its relative price.

The figure makes this concrete. Two agents, two goods, aggregate endowment \(\bar e=(1,1)\), \(u^A=a\log x_1+(1-a)\log x_2\), \(u^B=b\log x_1+(1-b)\log x_2\). Normalize prices so that \(p_1+p_2=1\), i.e. \(p\cdot\bar e=1\). With Cobb–Douglas utilities the FOC gives \(p_lx^i_l=a^i_l/\mu_i\); summing over goods, \(1/\mu_i=p\cdot e^i\). With this normalization the Negishi weight of each agent is her share of aggregate wealth, and the weights sum to one automatically. (Exercise 23.4 derives all of this in general.)

Interactive. Drag the endowment point \(e\) (A's endowment, measured from A's origin at bottom-left). The figure computes the competitive equilibrium: the black budget line through \(e\) has the equilibrium slope, the black dot is the CE allocation on the dashed violet contract curve, and the blue and orange curves are A's and B's indifference curves through it. Try: (1) drag \(e\) up and to the right (A gets richer): her weight \(\lambda_A\) rises, her \(\mu_A\) falls, and with \(a>b\) the price of good 1 rises. (2) Drag \(e\) along the line through the CE allocation parallel to the budget line: the equilibrium does not move, because only the value of each endowment matters. (3) Set \(a=b\): now \(p_1/p_2\) stays put however you redistribute, which is the aggregation result of Lesson 24.

6. Negishi's method: computing a CE by solving a planner problem

The two theorems say that the set of CE allocations (for all endowment distributions) and the set of PO allocations (for all weights) are the same set, indexed differently. Negishi (1960) turned this into a way to find the CE for a given distribution of endowments: search over weights, not prices.

Negishi's algorithm
  1. Guess weights. Pick \(\lambda\) in the simplex \(\{\lambda\ge0:\sum_i\lambda_i=1\}\).
  2. Solve the planner. Solve \(W\) at these weights: get the allocation \(x^i(\lambda)\) and shadow values \(\gamma(\lambda)\).
  3. Check budgets. Treat \(\gamma(\lambda)\) as prices and compute the transfer each agent would need, \(T^i(\lambda)=\gamma(\lambda)\cdot\big(x^i(\lambda)-e^i\big)\). These always sum to zero, because \(\sum_ix^i(\lambda)=\bar e=\sum_ie^i\).
  4. Stop or update. If \(T^i(\lambda)=0\) for all \(i\), the planner's allocation is affordable from each agent's own endowment: by the 2WT argument, \((\gamma(\lambda),x(\lambda))\) is a CE with no transfers. Otherwise raise the weight of agents with \(T^i\lt0\) (the planner gives them less than they can afford) and lower it for agents with \(T^i>0\). Go back to Step 2.

What it buys you:

Interactive: Negishi's algorithm. Same economy as above (\(a=0.7\), \(b=0.3\)). Choose a weight \(\lambda_A\) with the slider. The violet dot is the planner's allocation \(x(\lambda)\), and the black line through it has slope \(-\gamma_1/\gamma_2\). The grey dashed line is the parallel line through the endowment \(e\). The gap between the two lines is the transfer \(T^A\), measured in units of good 2 (with \(\gamma_1+\gamma_2=1\)). Try: press "Negishi step" repeatedly from \(\lambda_A=\tfrac12\). Each step sets the new weight equal to A's wealth at the current shadow prices, \(\lambda_A\leftarrow\gamma(\lambda)\cdot e^A\), and the two lines merge within a few steps. Drag \(e\) and repeat.

Why the update works here: with Cobb–Douglas utilities, the value of the planner's bundle for A at shadow prices is exactly \(\gamma\cdot x^A(\lambda)=\lambda_A\) (Exercise 23.4). So the budget condition \(T^A=0\) reads \(\lambda_A=\gamma(\lambda)\cdot e^A\), a fixed-point equation in one unknown. The map \(\lambda_A\mapsto\gamma(\lambda)\cdot e^A\) has slope \((a-b)(e_1-e_2)\), which is less than one in absolute value, so iterating it converges.

7. Check your understanding

1. In the household FOC \(u^i_l=\mu_ip_l\), what does \(\mu_i\) measure?
  • Agent i's utility gain per extra dollar
  • Agent i's weight in every planner problem
  • The price of good l for agent i
  • The social value of the endowment e
By the envelope theorem, \(\mu_i=\partial V^i/\partial w\): the marginal utility of income. The planner weight is its inverse (up to \(\kappa\)), not \(\mu_i\) itself. The social value of goods is \(\gamma\).
2. A CE allocation solves the planner problem \(W\) with which weights?
  • \(\lambda_i=\kappa/\mu_i\): richer agents get larger weights
  • \(\lambda_i=\kappa\mu_i\): poorer agents get larger weights
  • \(\lambda_i=\kappa\): all agents get equal weights
  • \(\lambda_i=\kappa\,p\cdot e^i\): wealth itself, for any preferences
Divide \(u^i_l=\mu_ip_l\) by \(\mu_i\) to get the planner's FOC with \(\lambda_i=1/\mu_i\) (times any \(\kappa>0\)). The weight equals wealth \(p\cdot e^i\) only for special utility functions, such as Cobb–Douglas with shares summing to one (Exercise 23.4).
3. Which assumption does the FOC proof of the 1WT need that the proof in Lesson 4 does not?
  • Concavity of each utility function \(u^i\)
  • Local non-satiation of every household's preferences
  • A finite number of commodities m
  • Price-taking behaviour by all the households
Concavity makes the planner's FOCs sufficient (Step 5). LNS is implied by strict monotonicity in both proofs; finiteness of the value of the endowment and price-taking are used by both.
4. In the FOC proof of the 2WT, how are the endowments chosen?
  • Each agent is endowed with its PO bundle
  • Each agent keeps its original endowment vector unchanged
  • Each agent gets an equal share of ē
  • Each agent gets endowments proportional to its weight
\(e^i=\bar x^i\), so the bundle is affordable with a binding budget. Any endowment with the same value \(p\cdot e^i=p\cdot\bar x^i\) works too; the difference from the original endowments is a balanced lump-sum transfer.
5. Two agents have different Cobb–Douglas shares. Moving endowment from A to B changes \(p_1/p_2\) because…
  • aggregate demand weights each agent's shares by wealth
  • the aggregate endowment of each good also changes
  • the planner's weights stay fixed when endowments move
  • marginal rates of substitution are no longer equalized
Aggregate spending on good 1 is \(a\,w^A+b\,w^B\). Shifting wealth changes it unless \(a=b\). The aggregate endowment is fixed, the weights move with the endowments, and MRSs are always equalized in a CE.
6. Agent 1's utility \(u^1\) is replaced by \(2u^1\). What happens to her Negishi weight?
  • It halves, while the allocation stays the same
  • It doubles, while the allocation stays the same
  • It is unchanged, and so is the allocation
  • It halves, and agent 1 consumes less now
Preferences are unchanged, so the CE is unchanged. Every \(u^1_l\) doubles at the same prices, so \(\mu_1\) doubles and \(\lambda_1=\kappa/\mu_1\) halves: \(\lambda_1\cdot2u^1\) has the same marginal value as before. Weights are tied to a utility representation.

8. Exercises

On past Alvarez exams this material shows up in two ways: true/false statements on the mapping \(\lambda_i=1/\mu_i\), \(\gamma=p\) (Fall 2005, Fall 2025), and envy-freeness of equal-division equilibria (Fall 2025). The derivations below are in exam format, with general parameters.

True or false? Justify. Past exam Exam-inspired

Answer True or False and justify in at most four lines.

  1. Let \(\mu_i\) be agent \(i\)'s marginal utility of income, \(p_s\) the price of the good in state \(s\), \(\lambda_i\) agent \(i\)'s planner weight and \(\gamma_s\) the marginal social value of good \(s\). Setting \(\lambda_i=\mu_i\) and \(\gamma_s=p_s\) makes the planner's allocation coincide with the CE allocation. Fall 2005 Midterm, Ex. 1 Q5
    Answer

    False. The CE FOC is \(u^i_s=\mu_ip_s\); the planner's is \(\lambda_iu^i_s=\gamma_s\). With \(\gamma=p\) they coincide iff \(\lambda_i=1/\mu_i\). Under \(\lambda_i=\mu_i\), the planner would favour agents with a high marginal utility of income, i.e. the poor, the opposite of a CE. (The statement holds only in the knife-edge case \(\mu_i=1\) for all \(i\).)

  2. In the same setting, setting \(\lambda_i=\kappa/\mu_i\) and \(\gamma_s=\kappa p_s\) for an arbitrary \(\kappa>0\) makes the two allocations coincide. exam-inspired variant
    Answer

    True (for interior allocations with concave, differentiable utility). Multiplying \(u^i_s=\mu_ip_s\) by \(\kappa/\mu_i\) gives \(\lambda_iu^i_s=\gamma_s\). The planner problem is invariant to scaling all weights by \(\kappa\), and \(\gamma\) scales with it CN3 p.21.

  3. Pure endowment economy; all utilities strictly concave, strictly increasing, differentiable, satisfying Inada conditions. In a CE, the price of each good is proportional to a weighted average across agents of that good's marginal utility, with the same weights for every good. Fall 2025 MT1 I.4
    Answer

    True. Inada makes demands interior, so \(p_l=\frac1{\mu_i}u^i_l\) for every \(i\). Averaging over \(i\) with any fixed weights \(\omega_i\) gives \(p_l=\sum_i\omega_i\frac1{\mu_i}u^i_l\): weights \(\omega_i/\mu_i\), proportional to the Negishi weights, the same for every good because each agent has a single budget multiplier. Equivalently, \(p_l=\gamma_l\), the representative agent's marginal utility of good \(l\).

  4. The statement in item 3 remains true if the Inada conditions are dropped and the weights must be strictly positive. exam-inspired (Exercise 23.2)
    Answer

    False in general. At a corner, \(u^i_l\le\mu_ip_l\) with strict inequality for goods \(i\) does not consume. Then \(p_l=\max_iu^i_l/\mu_i\), and a positively weighted average of \(u^i_l/\mu_i\) undershoots \(p_l\) for some goods but not others, so it is not proportional to \(p\). Exercise 23.2 works this out.

  5. At an interior PO allocation solving \(W\), \(\dfrac{u^i_l}{u^j_l}=\dfrac{\lambda_i}{\lambda_j}\): the agent with the larger weight has the larger marginal utility. exam-inspired (a review-sheet error)
    Answer

    False. From \(\lambda_iu^i_l=\gamma_l\), \(u^i_l/u^j_l=\lambda_j/\lambda_i\). A larger weight means a lower marginal utility, i.e. more consumption CN3 p.16. A commonly circulated summary table has this ratio upside down.

  6. The FOC proof of the 1WT shows that a CE is Pareto optimal whenever preferences satisfy local non-satiation. exam-inspired
    Answer

    False. The conclusion holds under LNS (Lesson 4), but the FOC proof needs differentiability, concavity (so the planner's FOCs are sufficient), interior allocations and pure exchange. LNS alone gives none of these.

  7. In the FOC proof of the 2WT, every agent keeps her original endowment, so no transfers are needed. exam-inspired
    Answer

    False. The proof sets \(e^i=\bar x^i\). Relative to original endowments \(\omega^i\), this is a transfer \(T^i=p\cdot(\bar x^i-\omega^i)\), and \(\sum_iT^i=0\). No transfers are needed only if \(p\cdot\omega^i=p\cdot\bar x^i\) for all \(i\) already, i.e. \(\lambda\) happens to be the CE weight of the original endowments.

  8. In a pure exchange economy, equilibrium relative prices do not depend on how the aggregate endowment is distributed across agents. exam-inspired (slide 25)
    Answer

    False in general. With \(u^A=a\log x_1+(1-a)\log x_2\), \(u^B=b\log x_1+(1-b)\log x_2\), \(\bar e=(1,1)\) and \(p_1+p_2=1\), we get \(p_1=b+\lambda_A(a-b)\) where \(\lambda_A\) is A's wealth share; it moves with the distribution unless \(a=b\) (see the first figure). Independence requires special preferences: Lesson 24.

  9. Consider a pure endowment economy with \(I\) agents and \(e^i=\bar e/I\) for all \(i\). The CE allocation is envy-free: \(u^i(\bar x^i)\ge u^i(\bar x^j)\) for all \(i,j\). Fall 2025 MT1 I.6
    Answer

    True. Every agent has wealth \(p\cdot\bar e/I\), so all budget sets are the same set. Each \(\bar x^j\) lies in it, hence in \(i\)'s budget set; since \(\bar x^i\) is optimal for \(i\) there, \(u^i(\bar x^i)\ge u^i(\bar x^j)\). Nothing else (LNS, convexity, identical preferences) is needed.

  10. A CE allocation can be envy-free only if all agents have equal endowments. exam-inspired (a review-sheet error)
    Answer

    False. Equal endowments are sufficient (item 9), not necessary. Example: \(u^1=x_1\), \(u^2=x_2\), \(e^1=(1,0)\), \(e^2=(0,1)\). At any \(p\gg0\), each agent keeps her endowment, and with \(p=(1,10)\) agent 2 is ten times richer. Neither envies the other: agent 1 values agent 2's bundle at 0. (A commonly circulated answer key justifies a related statement with "envy-freeness requires equal endowments"; that justification is wrong.)

Exercise 23.1 Exam-inspired (the budget multiplier, from scratch)

Agent \(i\) has a strictly increasing, strictly concave, differentiable \(u^i\) on \(\mathbb R^m_+\) satisfying Inada conditions, faces prices \(p\gg0\), and has wealth \(w>0\).

  1. Write the Lagrangian, including non-negativity constraints, and the Kuhn–Tucker conditions. (5 pts)
  2. Show that the budget binds and that \(\mu_i>0\). Which assumption did you use? (5 pts)
  3. Show that \(\partial V^i(p,w)/\partial w=\mu_i\). (10 pts)
  4. Show that \(V^i(p,\cdot)\) is concave, and conclude that \(\mu_i\) is non-increasing in \(w\). (10 pts)
  5. Two agents have the same \(u\) and face the same \(p\), with \(w^1>w^2\). Rank their Negishi weights. Can you rank them if their utility functions differ? One line each. (5 pts)
Hint

For (c), differentiate the identity \(p\cdot x^*(p,w)=w\) with respect to \(w\). For (e), recall that \(\lambda_i\propto1/\mu_i\) and that \(\mu_i\) scales with the utility representation.

Show solution

(a) \(\mathcal L=u^i(x)+\mu_i(w-p\cdot x)+\sum_l\nu_lx_l\). Conditions: \(u^i_l-\mu_ip_l+\nu_l=0\); \(\mu_i\ge0\), \(\mu_i(w-p\cdot x)=0\); \(\nu_l\ge0\), \(\nu_lx_l=0\). Inada gives \(x_l>0\), so \(\nu_l=0\) and \(u^i_l=\mu_ip_l\).
(b) \(u^i_l>0\) (strictly increasing; Inada gives \(u_l\to\infty\) at zero, and differentiable strictly concave increasing functions have \(u_l>0\) in the interior), so \(\mu_i=u^i_l/p_l>0\) and complementary slackness makes the budget bind. This is local non-satiation in action.
(c) \(V^i=u^i(x^*(p,w))\), so \(V^i_w=\sum_lu^i_l\,x^*_{l,w}=\mu_i\sum_lp_lx^*_{l,w}=\mu_i\), using \(\sum_lp_lx^*_{l,w}=1\) from the binding budget.
(d) For \(w,w'\) with optimal \(x,x'\) and \(t\in(0,1)\): \(tx+(1-t)x'\) costs \(tw+(1-t)w'\) and is in \(\mathbb R^m_+\), so \(V^i(p,tw+(1-t)w')\ge u^i(tx+(1-t)x')\ge tV^i(p,w)+(1-t)V^i(p,w')\). A concave function's derivative \(\mu_i=V^i_w\) is non-increasing. (Strict concavity of \(u\) makes \(V\) strictly concave whenever \(x\neq x'\), so \(\mu\) is strictly decreasing.)
(e) Same \(u\), same \(p\): \(\mu^1=V_w(p,w^1)\lt V_w(p,w^2)=\mu^2\), so \(\lambda_1>\lambda_2\): the richer agent gets the larger weight. With different \(u^i\), no: multiplying \(u^1\) by a constant changes \(\mu_1\) and \(\lambda_1\) without changing anything real, so cross-agent comparisons of \(\mu\) are not meaningful.

Exercise 23.2 Past exam: Fall 2025 MT1 I.4, extended (prices as weighted marginal utilities, with and without corners)

Pure exchange, \(I\) agents, \(m\) goods, each \(u^i\) strictly increasing, strictly concave, differentiable. Let \((p,\{\bar x^i\})\) be a CE with budget multipliers \(\mu_i\).

  1. Assume Inada conditions. Show that for any weights \(\omega_i\ge0\) summing to one, \(p_l=\sum_i\tilde\lambda_iu^i_l(\bar x^i)\) with \(\tilde\lambda_i=\omega_i/\mu_i\), for all \(l\). Why are the weights the same for all goods? (10 pts)
  2. Interpret \(p_l\) as the marginal utility of good \(l\) for a representative agent with utility \(u(x;\lambda)\), \(\lambda_i=1/\mu_i\). (5 pts)
  3. Now drop Inada conditions. Write the Kuhn–Tucker condition for good \(l\) and show that \(p_l=\max_i u^i_l(\bar x^i)/\mu_i\). (10 pts)
  4. Suppose agent 2 consumes none of good 1 but positive amounts of good 2, while agent 1 consumes both. Show that no average with strictly positive weights \(\omega_1,\omega_2\) of \(u^i_l/\mu_i\) is proportional to \(p\). (10 pts)
Show solution

(a) Interior demands: \(u^i_l=\mu_ip_l\), so \(u^i_l/\mu_i=p_l\) for each \(i\). Multiply by \(\omega_i\) and sum: \(\sum_i\omega_iu^i_l/\mu_i=p_l\sum_i\omega_i=p_l\). The weight \(\omega_i/\mu_i\) does not depend on \(l\) because \(\mu_i\) is the multiplier on \(i\)'s single budget constraint.
(b) By the 1WT via FOCs, \(\bar x\) solves the planner's allocation problem at \(\bar e\) with \(\lambda_i=1/\mu_i\) and multipliers \(\gamma=p\). By the envelope theorem, \(\partial u(\bar e;\lambda)/\partial x_l=\gamma_l=p_l\) (Lesson 22).
(c) \(u^i_l(\bar x^i)\le\mu_ip_l\), with equality if \(\bar x^i_l>0\). So \(u^i_l/\mu_i\le p_l\) for all \(i\), with equality for every agent who consumes good \(l\). Some agent consumes each good (markets clear with \(\bar e_l>0\)), so \(p_l=\max_iu^i_l/\mu_i\).
(d) For good 2, both agents consume it, so \(u^1_2/\mu_1=u^2_2/\mu_2=p_2\) and the average is \(p_2\). For good 1, \(u^1_1/\mu_1=p_1\) but \(u^2_1/\mu_2\lt p_1\), so the average is \(\omega_1p_1+\omega_2u^2_1/\mu_2\lt p_1\) when \(\omega_2>0\). The ratio of averages is below \(p_1/p_2\): not proportional. The statement survives only by putting zero weight on agent 2, so the Inada conditions in the exam statement do real work.

Exercise 23.3 Proof Slides pp.20–24 (both theorems, one dictionary)

Pure exchange; HH and CC; differentiable, strictly increasing utilities; all allocations interior.

  1. Prove: if \((p,\bar x)\) is a CE, then \(\bar x\) solves \(W\) for \(\lambda_i=\kappa/\mu_i\), and is PO. Mark the step where you use (i) concavity, (ii) \(\lambda\gg0\). (15 pts)
  2. Prove: if \(\bar x\) solves \(W\) for \(\lambda\gg0\), it is a CE for \(p=\gamma\) and endowments \(e^i=\bar x^i\). Which FOCs are you using as necessary and which as sufficient? (15 pts)
  3. The economy starts with endowments \(\omega^i\). Give the lump-sum transfers that implement \(\bar x\) as a CE and show they balance. (5 pts)
  4. Give an example in which the planner's FOCs hold at a point that is not Pareto optimal because \(u^i\) is not concave. Does this contradict the 1WT? (10 pts)
Hint

For (d), take one good, two agents, \(\bar e=1\), and \(u^i(x)=x^2\). Look at the equal split with equal weights.

Show solution

(a) See §3, Steps 1–6. Concavity is used in Step 5 (the planner's Lagrangian is concave, so its FOCs are sufficient); \(\lambda\gg0\) is used in Step 6 (a Pareto improvement would strictly raise \(\sum\lambda_iu^i\)). Household FOCs are used as necessary conditions in Step 1.
(b) See §4, Steps 1–6. The planner's FOCs are used as necessary (Step 1: \(\bar x\) is an interior maximizer with linear constraints); the household's FOCs as sufficient (Step 5: concave \(u^i\), linear budget). This is the slide's warning: "keep in mind when we use the necessity of the FOC and when we use its sufficiency" CN3 p.15.
(c) \(T^i=p\cdot(\bar x^i-\omega^i)\); then \(p\cdot\bar x^i=p\cdot\omega^i+T^i\), and \(\sum_iT^i=p\cdot(\sum_i\bar x^i-\sum_i\omega^i)=p\cdot(\bar e-\bar e)=0\).
(d) With \(u^i=x^2\), \(\lambda_1=\lambda_2=1\), the FOC \(2x^1=\gamma=2x^2\) holds at \(x^1=x^2=\tfrac12\), where \(\sum\lambda_iu^i=\tfrac12\). But \(x=(1,0)\) gives \(1\): the FOC point is a minimum of \(W\) on the feasible line. Is it PO? Every split of one good with increasing utilities is PO (you cannot raise one agent without lowering the other), so the equal split is PO, yet it solves \(W\) for no weights at all (\(\lambda_1x^2+\lambda_2(1-x)^2\) is convex in \(x\), so its maximum is always at a corner). No contradiction with the 1WT: with one good, the only CE is the endowment allocation, and it is PO, as Lesson 4 guarantees. What fails is the FOC method: without concavity, FOCs neither identify planner optima nor support PO allocations as CE (Lesson 21's non-convex utility possibility set).

Exercise 23.4 Exam-inspired (Negishi weights in a log economy, in general)

\(I\) agents, \(m\) goods, \(u^i(x)=\sum_la^i_l\log x_l\) with \(a^i_l>0\), \(\sum_la^i_l=1\). Endowments \(e^i\gg0\), aggregate \(\bar e=\sum_ie^i\). Write \(s^i_l=e^i_l/\bar e_l\) for agent \(i\)'s share of the endowment of good \(l\).

  1. Solve the planner problem \(W\) for weights \(\lambda\) with \(\sum_i\lambda_i=1\): find \(x^i_l(\lambda)\) and \(\gamma_l(\lambda)\). (10 pts)
  2. Show that \(\sum_l\gamma_l\bar e_l=1\) and that the value of agent \(i\)'s planner bundle at shadow prices is \(\gamma\cdot x^i(\lambda)=\lambda_i\). (10 pts)
  3. Show that \(\lambda\) is the CE weight vector for endowments \(\{e^i\}\) if and only if \(\lambda_i=\sum_jM_{ij}\lambda_j\) with \(M_{ij}=\sum_la^j_ls^i_l\). Show that every column of \(M\) sums to one, and interpret \(\lambda\). (10 pts)
  4. Let \(I=m=2\), \(\bar e=(1,1)\), \(a^A=(a,1-a)\), \(a^B=(b,1-b)\) and \(e^A=(e_1,e_2)\). Show that $$\lambda_A^*=\frac{b\,e_1+(1-b)\,e_2}{1-(a-b)(e_1-e_2)},\qquad \frac{p_1}{p_2}=\frac{b+\lambda_A^*(a-b)}{1-b-\lambda_A^*(a-b)} .$$ (10 pts)
  5. Show that \(p_1/p_2\) does not depend on \((e_1,e_2)\) if \(a=b\), and that it increases with \(\lambda^*_A\) if \(a>b\). Interpret. (5 pts)
  6. Negishi's update sets \(\lambda_A^{k+1}=\gamma(\lambda^k)\cdot e^A\). Show that this map is a contraction and that its fixed point is \(\lambda_A^*\). (5 pts)
Hint

(a) The planner FOC is \(\lambda_ia^i_l/x^i_l=\gamma_l\). Solve for \(x^i_l\) and sum over \(i\). (c) By the 2WT argument, \(\lambda\) is a CE weight iff \(\gamma(\lambda)\cdot x^i(\lambda)=\gamma(\lambda)\cdot e^i\) for every \(i\).

Show solution

(a) \(x^i_l=\lambda_ia^i_l/\gamma_l\). Feasibility \(\sum_ix^i_l=\bar e_l\) gives \(\gamma_l=\sum_j\lambda_ja^j_l/\bar e_l\), hence \(x^i_l=\dfrac{\lambda_ia^i_l}{\sum_j\lambda_ja^j_l}\,\bar e_l\): each agent gets a share of each good proportional to \(\lambda_ia^i_l\).
(b) \(\sum_l\gamma_l\bar e_l=\sum_j\lambda_j\sum_la^j_l=\sum_j\lambda_j=1\). And \(\gamma\cdot x^i=\sum_l\gamma_l\lambda_ia^i_l/\gamma_l=\lambda_i\sum_la^i_l=\lambda_i\).
(c) CE weight iff budgets balance: \(\lambda_i=\gamma(\lambda)\cdot e^i=\sum_le^i_l\sum_j\lambda_ja^j_l/\bar e_l=\sum_j\lambda_j\sum_la^j_ls^i_l\). Column sums: \(\sum_iM_{ij}=\sum_la^j_l\sum_is^i_l=\sum_la^j_l=1\). So \(M\) is column-stochastic with positive entries and \(\lambda\) is its Perron eigenvector with eigenvalue 1, unique on the simplex. With the normalization \(\gamma\cdot\bar e=1\), \(\lambda_i=\gamma\cdot e^i\) is agent \(i\)'s share of aggregate wealth: here, the Negishi weight is wealth.
(d) \(\gamma_1=\lambda_Aa+(1-\lambda_A)b=b+\lambda_A(a-b)\) and \(\gamma_2=1-\gamma_1\). Budget balance for A: \(\lambda_A=\gamma_1e_1+\gamma_2e_2=be_1+(1-b)e_2+\lambda_A(a-b)(e_1-e_2)\). Solve for \(\lambda_A^*\). Prices are \(p=\gamma(\lambda^*)\).
(e) If \(a=b\), \(\gamma_1=a\) for every \(\lambda\): \(p_1/p_2=a/(1-a)\), independent of the distribution. If \(a>b\), \(\gamma_1\) rises with \(\lambda_A\): richer A, who values good 1 more, raises its relative price. Identical homothetic preferences are exactly what kills the dependence (Lesson 24).
(f) The map is \(\phi(\lambda_A)=be_1+(1-b)e_2+(a-b)(e_1-e_2)\lambda_A\). Its slope satisfies \(|(a-b)(e_1-e_2)|\lt1\) because \(a,b,e_1,e_2\in(0,1)\). So \(\phi\) is a contraction, the iterates converge to its unique fixed point, and that fixed point is \(\lambda_A^*\) from (d). (This is what the "Negishi step" button computes.)

Exercise 23.5 Past exam: Fall 2025 MT1 I.6, extended (envy-free allocations)

Pure exchange, \(I\) agents, \(m\) goods. A feasible allocation is envy-free if \(u^i(x^i)\ge u^i(x^j)\) for all \(i,j\).

  1. Show that if \(e^i=\bar e/I\) for all \(i\), every CE allocation is envy-free. List the assumptions you used. (10 pts)
  2. Show by example that a CE allocation can be envy-free even with unequal endowments and unequal wealth. (5 pts)
  3. Let \(u^i=g^i(h(x))\) with \(h\) homogeneous of degree one, \(h(\bar e)>0\), \(g^i\) strictly increasing, and \(e^i=\delta^i\bar e\). Taking as given (Lesson 24) that the CE allocation is \(\bar x^i=\delta^i\bar e\), show that it is envy-free if and only if all \(\delta^i=1/I\). (10 pts)
  4. Under LNS, the equal-division CE is both envy-free and Pareto optimal. In one line, why does this mean "efficiency and fairness are compatible" in exchange economies? (5 pts)
Show solution

(a) All agents have wealth \(p\cdot\bar e/I\) and face the identical budget set \(B=\{x\in X: p\cdot x\le p\cdot\bar e/I\}\) (assuming a common consumption set). Each \(\bar x^j\in B\). If \(u^i(\bar x^j)>u^i(\bar x^i)\), agent \(i\) could have chosen \(\bar x^j\), contradicting optimality. Assumptions used: only that each agent maximizes over the same budget set. No LNS, convexity, differentiability or identical preferences.
(b) \(u^1=x_1\), \(u^2=x_2\), \(e^1=(1,0)\), \(e^2=(0,1)\). For any \(p\gg0\), agent 1 spends everything on good 1 and agent 2 on good 2, so the endowment is the CE allocation (for example with \(p=(1,10)\), so wealths are 1 and 10). Each agent values the other's bundle at 0 \(\lt1\): envy-free.
(c) \(u^i(\bar x^j)=g^i(\delta^jh(\bar e))\). Envy-free requires \(g^i(\delta^ih(\bar e))\ge g^i(\delta^jh(\bar e))\) for all \(i,j\), i.e. \(\delta^i\ge\delta^j\) for all \(i,j\), i.e. all \(\delta^i\) equal, \(=1/I\). Conversely, equal shares give equal bundles, and nobody envies an identical bundle.
(d) The equal-division CE exists under standard assumptions (continuity, convexity and monotonicity of preferences) and is PO by the 1WT, so a fair (envy-free and efficient) allocation exists. This is Varian's (1974) observation in "Equity, envy, and efficiency," Journal of Economic Theory.

Exercise 23.6 Problem set (2022) PS3 P1 (security markets: when are the marginal valuations common?)

There are \(S\) states and one good per state. Agent \(i\) has endowment \(e^i\in\mathbb R^S_{++}\) and strictly concave, increasing, differentiable \(u^i(x)\). There are \(K\) securities; security \(k\) pays \(d_{ks}\) in state \(s\) and costs \(q_k\). Agent \(i\) buys a portfolio \(a^i\in\mathbb R^K\) with \(\sum_kq_ka^i_k\le0\) and consumes \(x^i_s=e^i_s+\sum_kd_{ks}a^i_k\). Let \(\mu^i\) be the multiplier on the portfolio budget and define \(\eta^i_s\equiv u^i_s(x^i)/\mu^i\).

  1. Show that the FOC for \(a^i_k\) is \(q_k=\sum_sd_{ks}\eta^i_s\). Interpret \(\eta^i_s\). (5 pts)
  2. Suppose the equilibrium allocation is (interior and) PO. Show that \(\eta^i_s\) is the same for all agents. (10 pts)
  3. A circulating solution argues: "PO means the allocation solves \(W\) with \(\lambda_i=1/\mu^i\) and \(\gamma=\eta\), so \(\eta^i=\eta\)." What is wrong with this argument? (5 pts)
  4. Markets are incomplete and the \(\eta^i\) differ across agents. Is the allocation PO? (5 pts)
Show solution

(a) \(\partial/\partial a^i_k\): \(\sum_su^i_sd_{ks}=\mu^iq_k\); divide by \(\mu^i\). \(\eta^i_s\) is agent \(i\)'s marginal valuation, in units of account, of one unit of consumption in state \(s\): her personal state price.
(b) PO and interiority imply equal MRS: \(u^i_s/u^i_1=g_s\equiv\gamma_s/\gamma_1\) for every \(i\). Then \(\eta^i_s=g_s\,\eta^i_1\). Plug into (a): \(q_k=\eta^i_1\sum_sd_{ks}g_s\), so \(\eta^i_1=q_k/\sum_sd_{ks}g_s\) for any \(k\) with \(q_k\neq0\). The right side does not depend on \(i\), so \(\eta^i_1\) and therefore every \(\eta^i_s\) is common.
(c) It assumes the conclusion. \(\mu^i\) is determined by agent \(i\)'s own budget, not chosen freely. PO gives some weights \(\lambda\) with \(\lambda_iu^i_s=\gamma_s\); that \(\lambda_i\) can be taken equal to \(1/\mu^i\) (up to a common \(\kappa\)) is what has to be shown, and it is shown by the argument in (b) using the securities' pricing equations.
(d) No. If \(\eta^i\neq\eta^j\), they cannot be proportional: \(\eta^i=c\,\eta^j\) would give \(q=c\,q\), so \(c=1\) (for \(q\neq0\)). Non-proportional \(\eta\) vectors mean \(u^i_s/u^i_{s'}\neq u^j_s/u^j_{s'}\) for some \(s,s'\): unequal MRS, which violates the planner's FOCs, so a Pareto improvement exists. With complete markets (the payoff matrix has rank \(S\)), \(q=D\eta^i\) pins down \(\eta^i\) uniquely, so it is common and the allocation is PO.

Exercise 23.7 Problem set (2022) PS3 P2(d) (what Pareto weights do under uncertainty: CARA risk sharing)

One good in each of \(S\) states, common probabilities \(\pi_s>0\), aggregate endowment \(\bar e_s\). Agent \(i\) has expected utility \(\sum_s\pi_sv^i(x^i_s)\) with CARA \(v^i(x)=-e^{-\rho_ix}/\rho_i\), \(\rho_i>0\). Let \(R=\sum_j1/\rho_j\).

  1. Write the planner's FOC and solve for \(x^i_s\) in terms of \(\lambda_i\), \(\pi_s\), \(\gamma_s\). (5 pts)
  2. Using the normalization \(\sum_i\rho_i^{-1}\log\lambda_i=0\), show that \(x^i_s=\dfrac{1/\rho_i}{R}\,\bar e_s+\dfrac{1}{\rho_i}\log\lambda_i\). (10 pts)
  3. Interpret: how is aggregate risk shared, and what do the Pareto weights change? (5 pts)
  4. Show that \(\gamma_s/\gamma_{s'}\) does not depend on \(\lambda\), even though preferences are not identical. (5 pts)
Show solution

(a) \(\lambda_i\pi_se^{-\rho_ix^i_s}=\gamma_s\), so \(x^i_s=\frac{1}{\rho_i}\big[\log\lambda_i+\log\pi_s-\log\gamma_s\big]\).
(b) Sum over \(i\): \(\bar e_s=\sum_i\rho_i^{-1}\log\lambda_i+R(\log\pi_s-\log\gamma_s)=R(\log\pi_s-\log\gamma_s)\). So \(\log\pi_s-\log\gamma_s=\bar e_s/R\), and substituting gives the result.
(c) Each agent bears a fixed fraction \((1/\rho_i)/R\) of aggregate risk, her share of total risk tolerance. The weights only shift each agent's consumption by a state-independent constant \(\rho_i^{-1}\log\lambda_i\): higher weight, more consumption in every state. In a CE this constant is pinned down by the agent's wealth, exactly as \(\lambda_i\propto1/\mu_i\) says.
(d) From (b), \(\gamma_s=\pi_se^{-\bar e_s/R}\), so \(\gamma_s/\gamma_{s'}=(\pi_s/\pi_{s'})e^{-(\bar e_s-\bar e_{s'})/R}\), free of \(\lambda\). CARA demands shift one-for-one with wealth in a way that is common across agents, so redistribution does not change aggregate demand. This is a preview of when aggregation holds (Lessons 24–25), and a contrast with Exercise 23.4, where different Cobb–Douglas shares break it.

Key takeaways

💬 Stuck or curious? Ask me (your Claude teacher) anything. Try "why does Negishi's update converge in general, not just for Cobb–Douglas?" or "redo Exercise 23.4 with CRRA utility and show where the weights enter the prices."
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